\(f(3)\)-ро ҳисоб кунед, агар \(f(x)=\frac{x}{4}+\frac{5}{x}+\frac{7}{12}\)

\(f(3)=\frac{3}{4}+\frac{5}{3}+\frac{7}{12}=\)

\(=\frac{9}{12}+\frac{5}{3}+\frac{7}{12}=\)

\(=\frac{16}{12}+\frac{5}{3}=\)

\(=\frac{4}{3}+\frac{5}{3}=\)

\(=\frac{9}{3}=\)

\(=3\)

Ҷавоб: 3